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quickest (i blv) way to get the current program name minus the path (BASH)
Useful in shell scripts when you're trying to get the shell script name without the full path - and easier than awking or cutting. Bash pattern matching and variable manip is fun.

check open ports without netstat or lsof

Get full directory path of a script regardless of where it is run from
Also resolves symlinks, showing the full path of the link target

Install pip with Proxy
Installs pip packages defining a proxy

run command on a group of nodes

shell equivalent of a boss button
Nobody wants the boss to notice when you're slacking off. This will fill your shell with random data, parts of it highlighted. Note that 'highlight' is the Perl module App::highlight, not "a universal sourcecode to formatted text converter." You'll also need Term::ANSIColor.

check open ports without netstat or lsof

Auto download Ubuntu 10.04 LTS with super fast zsync
Need to have rc iso pre-downloaded before running command.

Eliminate dead symlinks interactively in /usr/ recursevely
Its not mine... I get from textlive migration in gentoo : http://www.gentoo.org/proj/en/tex/texlive-migration-guide.xml

Get AWS temporary credentials ready to export based on a MFA virtual appliance
You might want to secure your AWS operations requiring to use a MFA token. But then to use API or tools, you need to pass credentials generated with a MFA token. This commands asks you for the MFA code and retrieves these credentials using AWS Cli. To print the exports, you can use: `awk '{ print "export AWS_ACCESS_KEY_ID=\"" $1 "\"\n" "export AWS_SECRET_ACCESS_KEY=\"" $2 "\"\n" "export AWS_SESSION_TOKEN=\"" $3 "\"" }'` You must adapt the command line to include: * $MFA_IDis ARN of the virtual MFA or serial number of the physical one * TTL for the credentials


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