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Shows cpu load in percent

Terminal - Shows cpu load in percent
sed -e 's/ .*//' -e 's/\.//' -e 's/^0*//' /proc/loadavg
2014-04-18 19:12:05
User: flatcap
Functions: sed
5
Shows cpu load in percent

Show the current load of the CPU as a percentage.

Read the load from /proc/loadavg and convert it using sed:

Strip everything after the first whitespace:

sed -e 's/ .*//'

Delete the decimal point:

sed -e 's/\.//'

Remove leading zeroes:

sed -e 's/^0*//'

Alternatives

There are 2 alternatives - vote for the best!

Terminal - Alternatives
top -bn2|awk -F, '/Cpu/{if (NR>4){print 100-gensub(/.([^ ]+).*/,"\\1","g",$4)}}'
2014-04-18 17:48:05
User: ichbins
Functions: awk top
Tags: top cpu cpuinfo
1

This version is precise and requires one second to collect statistics. Check sample output for a more generic version and also a remote computer invocation variant. It doesn't work with the busybox version of the 'top' command but can be adjusted

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What others think

echo $(sed -e 's/ .*//' -e 's/\.//' -e 's/^0*//' /proc/loadavg)%

Comment by mpb 23 weeks and 2 days ago

@mqb: Or you could just alter the first sed clause:

sed -e 's/ .*/%/' -e 's/\.//' -e 's/^0*//' /proc/loadavg
Comment by flatcap 23 weeks and 2 days ago

Load average is not a percentage. From `man 1 uptime` : "...a load average of 1 means a single CPU system is loaded all the time while on a 4 CPU system it means it was idle 75% of the time."

Comment by Mozai 22 weeks ago

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