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Functions

Execute a command with the last parameter of a previous command

Terminal - Execute a command with the last parameter of a previous command
ls !$
2009-04-07 12:31:06
Functions: ls
1
Execute a command with the last parameter of a previous command

Suppose that you had change in a directory like /home/user/mycode/code, and now you need to list it, instead of type entire path again, use ls !$ to recall path and list. Useful with many commands, this is only an example. (In this case, same result can be achivied with ls .)

Alternatives

There are 2 alternatives - vote for the best!

Terminal - Alternatives

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What others think

I discovered this command by myself today,I don't copied it. ;-)

Comment by servermanaged 284 weeks and 6 days ago

I think this highlights that it is not so easy for users to search the existing command-line-fu to check if some idea has already been suggested.

"grep the archive" won't always find it.

Comment by mpb 284 weeks and 6 days ago

if you grep for exact command (ls !$) you intend to put down, it's highly unlikely to have a match. However, if you grep the archive more conceptually(e.g use of !$, in this case), then there's better chance to prevent duplications. For instance, if you grep for "!$" there are several entries regarding it.

Comment by alperyilmaz 284 weeks and 6 days ago

No one here thinks you "copied" it. This isn't the SATs, it's *nix. It's entirely based on reusing others' code; copying if you will.

What people are trying to bring to your attention, is that there is a fscking search bar readily available. If you would have tried searching for "previous command" or "last parameter" you most certainly would have found the above mentioned duplicates.

I counted 6 by searching a few keywords, and I'm sure I missed a ton.

Comment by sudopeople 284 weeks and 6 days ago

Ok ;)

Comment by servermanaged 284 weeks and 6 days ago

Your point of view

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