opening your helper script without knowing the path (zsh)

less =rcsyslog
This is equivalent to: less `which rcsyslog`

0
By: H4rpy
2009-02-22 14:07:41

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  • I find it useful when I want to add another crontab entry and I need to specify the appropriate PATH. I give ''whichpath'' a list of programs that I use inside my script and it gives me the PATH I need to use for this script. ''whichpath'' uses associative array, therefore you should have Bash v4 in order to run it. See sample output. Show Sample Output


    0
    whichpath() { local -A path; local c p; for c; do p=$(type -P "$c"); p=${p%/*}; path[${p:-/}]=1; done; local IFS=:; printf '%s\n' "${!path[*]}"; }
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  • Sometimes you need the full path to your script, regardless of how it was executed (which starting directory) in order to maintain other relative paths in the script. If you attempt to just use something simple like: STARTING_DIR="${0%/*}" you will only get the relative path depending on where you first executed the script from. You can get the relative path to the script (from your starting point) by using dirname, but you actually have to change directories and print the working directory to get the absolute full path. Show Sample Output


    0
    STARTING_DIR=$(cd $(dirname $0) && pwd)
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  • Often I need to edit a bash or perl script I've written. I know it's in my path but I don't feel like typing the whole path (or I don't remember the path).


    1
    vim `which <scriptname>`
    bunedoggle · 2009-05-08 17:21:47 2

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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