FizzBuzz in one line of Bash

for i in {1..100};do((i%3))&&x=||x=Fizz;((i%5))||x+=Buzz;echo ${x:-$i};done|column
The (in)famous "FizzBuzz" programming challenge, answered in a single line of Bash code. The "|column" part at the end merely formats the output a bit, so if "column" is not installed on your machine you can simply omit that part. Without "|column", the solution only uses 75 characters. The version below is expanded to multiple lines, with comments added. for i in {1..100} # Use i to loop from "1" to "100", inclusive. do ((i % 3)) && # If i is not divisible by 3... x= || # ...blank out x (yes, "x= " does that). Otherwise,... x=Fizz # ...set x to the string "Fizz". ((i % 5)) || # If i is not divisible by 5, skip (there's no "&&")... x+=Buzz # ...Otherwise, append (not set) the string "Buzz" to x. echo ${x:-$i} # Print x unless it is blanked out. Otherwise, print i. done | column # Wrap output into columns (not part of the test).
Sample Output
1        16       31       46       61       76       91
2        17       32       47       62       77       92
Fizz     Fizz     Fizz     Fizz     Fizz     Fizz     Fizz
4        19       34       49       64       79       94
Buzz     Buzz     Buzz     Buzz     Buzz     Buzz     Buzz
Fizz     Fizz     Fizz     Fizz     Fizz     Fizz     Fizz
7        22       37       52       67       82       97
8        23       38       53       68       83       98
Fizz     Fizz     Fizz     Fizz     Fizz     Fizz     Fizz
Buzz     Buzz     Buzz     Buzz     Buzz     Buzz     Buzz
11       26       41       56       71       86
Fizz     Fizz     Fizz     Fizz     Fizz     Fizz
13       28       43       58       73       88
14       29       44       59       74       89
FizzBuzz FizzBuzz FizzBuzz FizzBuzz FizzBuzz FizzBuzz

0
By: willdye
2017-08-22 15:44:16

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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