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recursively traverse the directory structure from . down, look for string "oldstring" in all files, and replace it with "newstring", wherever found
also:
grep -rl oldstring . |xargs perl -pi~ -e 's/oldstring/newstring'
There are 6 alternatives - vote for the best!
This command find all files in the current dir and subdirs, and replace all occurances of "oldstring" in every file with "newstring".
xargs deals badly with special characters (such as space, ' and "). To see the problem try this:
touch important_file
touch 'not important_file'
ls not* | xargs rm
Parallel https://savannah.nongnu.org/projects/parallel/ does not have this problem.
Using -Z with grep and -0 with xargs handles file names with spaces and special characters.
Search and replace recursively. :-) Shorter and simpler than the others. And allows more terms:
replace old new [old new ...] -- `find -type f`
If you can do better, submit your command here.
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so sweet and delicious
egrep might be better in some cases
find . -type f -exec grep -l XXX {} \;|tee /tmp/fileschanged|xargs perl -pi.bak -e 's/XXX/YYY/g'
Find all files that contain string XXX in them, change the string from XXX to YYY, make a backup copy of the file and save a list of files changed in /tmp/fileschanged.
find -type f | xargs sed -i -e '/oldstring/s,oldstring,newstring,'grep before using sed is unnecessary, it causes all files to be read and processed TWICE instead of just once.
Just use find and sed.
If you can install "rpl", have a look at man rpl. It does the same job more simply. I don't know how it would compare for speed though.
if you do this on a directory using subversion, ignore the .svn directories, or you'll get a surprise when asking for svn status.