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Show local/public IP adresses with or without interface argument using a shell function for Linux and MacOsX

Terminal - Show local/public IP adresses with or without interface argument using a shell function for Linux and MacOsX
MyIps(){ echo -e "local:\n$(ifconfig $1 | grep -oP 'inet (add?r:)?\K(\d{1,3}\.){3}\d{1,3}')\n\npublic:\n$(curl -s sputnick-area.net/ip)"; }
2009-12-06 22:52:31
User: sputnick
Functions: echo
1
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Show local/public IP adresses with or without interface argument using a shell function for Linux and MacOsX

Like the tiltle said, you can use an argument too ( the interface )

MyIps eth0

will show only the IP of this interface and the public IP

( tested with Linux )

You can add that function in ~/.bashrc, then

. ~/.bashrc

Now you are ready to call this function in all your terms...

Show sample output | Add to favourites | Report as malicious

Alternatives

There are 4 alternatives - vote for the best!

Terminal - Alternatives

Know a better way?

If you can do better, submit your command here.

What others think

This works on OS X (unlike almost all the other IP address commands that use ifconfig here) with the following changes: 1) change 'inet addr:' to 'inet ' and 2) ifconfig uses 'enX' rather than 'ethX' on linux.

So the command would be:

echo -e "local:\n$(ifconfig en0 | grep -oP 'inet \K(\d{1,3}\.){3}\d{1,3}')\n\npublic:\n$(curl -s sputnick-area.net/ip)";

to check the first ethernet IP address.

Comment by drewk 180 weeks and 4 days ago

Ok, thanks for your contribution. Here is the good one, for both MacOsX and Linux :

ifconfig $1 | grep -oP 'inet (addr:)?\K(\d{1,3}\.){3}\d{1,3}' 1 is an optionnal interface. That must works with or without.
Comment by polo 180 weeks and 4 days ago

So in complete :

MyIps(){ echo -e "local:\n$(ifconfig $1 | grep -oP 'inet (addr:)?\K(\d{1,3}\.){3}\d{1,3}')\n\npublic:\n$(curl -s sputnick-area.net/ip)"; }
Comment by polo 180 weeks and 4 days ago

Your point of view

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