Add member to domain group

net group groupname username /add /domain

0
2013-10-17 12:45:53

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    -2
    ldapsearch -H ldap://localhost:389 -D cn=username,ou=users,dc=domain -x -W -b ou=groups,dc=domain '(member=cn=username,ou=users,dc=domain)' | grep ^dn | sed "s/dn\: cn=\([^,]*\),ou=\([^,]*\),.*/\2 \1/"
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  • Group membership in OS X is a mish-mash of standards that end up meaning there's almost a half-dozen of ways to belong to a group, what with group inheritance and automatic assignment. This means there's no easy command to find out all groups a user belongs to. The only sensible way then is to list all users and then query each user for membership. NOTE: This is a function. Once input you can execute it by calling with a groupname. Show Sample Output


    -1
    members () { dscl . -list /Users | while read user; do printf "$user "; dsmemberutil checkmembership -U "$user" -G "$*"; done | grep "is a member" | cut -d " " -f 1; };
    eduo · 2012-05-20 11:34:33 0

  • -1
    net user USERNAME /domain
    shawn_abdushakur · 2014-01-02 20:22:46 0
  • ### for ADUSER in $(wbinfo -u --domain="$(wbinfo --own-domain)" | sort); do WBSEP=$(wbinfo --separator); ADUNAME=$(wbinfo -i "$ADUSER" | cut -d ":" -f5); UINFO=$(wbinfo -i "$ADUSER" | cut -d ":" -f4); SIDG=$(wbinfo -G "$UINFO"); GROUPID=$(wbinfo -s "$SIDG" | sed 's/.\{1\}$//' | cut -d "$WBSEP" -f2); echo -e "$ADUSER ($ADUNAME)\n$(printf '%.s-' {1..32})\n\t[*] $GROUPID"; for GID in $(wbinfo -r "$ADUSER"); do SID=$(wbinfo -G "$GID"); GROUP=$(wbinfo -s "$SID" | cut -d " " -f1,2); echo -e "\t[ ] $(echo -e "${GROUP/%?/}" | cut -d "$WBSEP" -f2)"; done | sed '1d'; echo -e "$(printf '%.s=' {1..32})\n"; done ### Show Sample Output


    0
    wbinfo - Get all users group membership, with primary group starred (Red description for full command)
    jaimerosario · 2014-06-20 20:45:52 0

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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