Show first IPv4 address for an interface without CIDR mask

ip addr show dev eth0 | grep -E '\binet\b' | sed 's|.*inet \([^/]*\)/.*|\1|' | head -n 1
Given a network interface (eth0 in this example), find its ip address, without CIDR netmask.
Sample Output
localhost core # ip addr show dev eth0 | grep -E '\binet\b' | sed 's|.*inet \([^/]*\)/.*|\1|' | head -n 1

2015-02-26 19:07:10

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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