Get just LAN IP without all the extra stuff

ip addr show | grep "inet " | while read INET IP TRASH; do if [ $IP != "127.0.0.1/8" ]; then echo $IP; exit 0; fi; done | sed s:/[1-9][1-9]:"":
I just needed to store the LAN IP (for ipv4) in a variable for a specific task in a bash script. I figured I'd share. I sent it to a variable with VAR=$(stuff) and used it later on. I put the exit 0 in the if statement to make it so that it breaks if there are more than one IPv4 addresses assigned. I only wanted the first one. Edit: Bear in mind, my network mask is a double digit number so if you have a smaller nw mask you'd need to edit the sed statement.
Sample Output
192.168.1.245

0
By: Meh
2016-04-07 17:46:20

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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