LIst svn commits by user for a date range

for i in `svn log -r{2011-02-01}:HEAD | awk '$3 == "user" {print $1}'`; do svn log -v -$i;done
Outputs a quick summary of the svn commits for a user over a date range with the detail revision logs including comments and files affected. Useful for searching for a particular change or reporting by user.
Sample Output
------------------------------------------------------------------------
r9717 | vijay | 2011-03-02 16:25:47 -0800 (Wed, 02 Mar 2011) | 2 lines
Changed paths:
   M /SDK/trunk/android-projects/pom.xml
   M /SDK/trunk/mobile-sdk/pom.xml
   M /SDK/trunk/mobile-itf/pom.xml
   M /SDK/trunk/pom.xml

pro-guard support added.
build profiles added.
------------------------------------------------------------------------
------------------------------------------------------------------------
r9724 | vijay | 2011-03-02 16:39:33 -0800 (Wed, 02 Mar 2011) | 1 line
Changed paths:
   M /SDK/trunk/pom.xml

minor pom correction
------------------------------------------------------------------------

1
2011-03-04 17:11:22
awk

1 Alternatives + Submit Alt

  • My script lists all users & the number of commits they made in the period, sorted alphabetically. To sort by number of commits, append a '|sort' to the end of the command. The script depends on the output format of svn log - original command didn't work for me because the string 'user' was not appearing in my output


    0
    svn log -r{2011-08-01}:HEAD|awk '$14 ~/line/ {print $3}'|sort|uniq -c
    sangnoir · 2011-09-01 07:58:54 0

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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