Take a file and ,."()?!;: give a list of all the words in order of increasing length. First of all use tr to map all alphabetic characters to lower case and also strip out any puntuation. A-Z become a-z ,."()?!;: all become \n (newline) I've ignored - (hyphen) and ' (apostrophe) because they occur in words. Next use bash to print the length ${#w} and the word Finally sort the list numerically (sort -n) and remove any duplicates (sort -u). Note: sort -nu performs strangely on this list. It outputs one word per length. Show Sample Output
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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$(wc -m <<< $a)
That's equivalent to "word\n" What you need is:$(echo -n $a | wc -m)