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find all minimum values in file with at least 100 lines

Terminal - find all minimum values in file with at least 100 lines
for ff in directory; do numLines=`wc -l $ff`; numLines=$(echo $numLines | sed 's/ .*//g'); min=$(sort -nrk 1 $ff | tail -1); if [ $numLines -gt 100 ]; then echo $min >> minValues; fi;done;
2013-09-23 04:04:52
User: user1234
Functions: echo sed sort tail
-1
find all minimum values in file with at least 100 lines

Alternatives

There are 6 alternatives - vote for the best!

Terminal - Alternatives

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What others think

Hmm... This could do with some tidying up.

First, I'd replace `wc -l $ff` with $(wc -l $ff)

It uses one more character, but $(...) can be nested and `...` cannot.

It's tempting to fold the two numLine assignments:

numLines=$(wc -l $ff | sed 's/ .*//g')

but I'd prefer to use bash and get rid of sed:

numLines=$(wc -l $ff) numLines=${numLines% *}

To save time, it's better to check the file length FIRST.

Currently, you sort all the small files, then ignore the result:

[ $numLines -lt 100 ] && continue

Now, you don't need the min variable any more:

sort -nrk 1 $ff | tail -1 >> minValues

Next, I'd change that sort line again.

Currently, it writes to 'minValues' one line at a time.

If you've got a LOT of files, it'd be more efficient to do:

sort -nrk 1 $ff | tail -1 done >> minValues

Finally, I'd quote the "$ff" just in case the filenames have whitespace in them.

for ff in directory/*; do numLines=$(wc -l "$ff"); numLines=${numLines% *}; [ $numLines -lt 100 ] && continue; sort -nrk 1 "$ff" | tail -1; done >> minValues

188 characters down to 157 :-)

Minimising it fully:

for f in directory/*;do n=$(wc -l "$f");n=${n% *};[ $n -lt 100 ]&&continue;sort -nrk 1 "$f"|tail -1;done>>minValues

115 characters

Comment by flatcap 53 weeks and 1 day ago

And... :-)

Swap &&continue;sort for ||sort

for f in directory/*;do n=$(wc -l "$f");n=${n% *};[ $n -lt 100 ]||sort -nrk 1 "$f"|tail -1;done>>minValues

106 characters

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Comment by shoesus53 53 weeks ago

Your point of view

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