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A command's package details

Terminal - A command's package details
dpkg -S `which nm` | cut -d':' -f1 | (read PACKAGE; echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}"; dpkg -L "${PACKAGE}") | less
2009-07-14 20:21:48
User: mohan43u
Functions: cut echo read
A command's package details

In Debian based distros, this command will list 'binutils' package details which contains 'nm' command. You can replace 'nm' to any other command.


There is 1 alternative - vote for the best!

Terminal - Alternatives
function summpkg { dpkg -s $(dpkg -S $1 | egrep -w $(which $1)$ | awk -F: '{print $1}') ; }
2011-07-05 23:06:37
User: b_t
Functions: awk egrep which
Tags: which dpkg

This version builds on my command 8776 (Find the package a command belongs to on debian-based distros). So if you use that command to find package name then you could alternatively use following for

package summary:

function summpkg { dpkg -s $(whichpkg $1 | awk -F: '{print $1}'); }
summpkg() { rpm -qfi "$@"; }
2011-07-05 23:39:24
User: flatcap
Functions: rpm
Tags: rpm

Find information about the rpm package which owns a certain file.

Know a better way?

If you can do better, submit your command here.

What others think

dlocate claims to be faster for some of these operations, although it returns more matches in the case of 'dlocate -S /usr/bin/nm'. Nice command!

Comment by bwoodacre 332 weeks and 2 days ago

You can simplify this slightly to eliminate "read":

dpkg -S `which nm` | cut -d':' -f1 | (read PACKAGE; echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}"; dpkg -L "${PACKAGE}") | less

Personally I'd leave out the dpkg -L call and less, and keep it short:

cmd(){ PACKAGE=$(dpkg -S $(which $1) | cut -d':' -f1); echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}" ;}
Comment by johnraff 311 weeks and 3 days ago

er... sorry I mispasted the first line, it should have been:

PACKAGE=$(dpkg -S $(which nm) | cut -d':' -f1 ); echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}"; dpkg -L "${PACKAGE}") | less
Comment by johnraff 311 weeks and 3 days ago

Your point of view

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