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May 19, 2015 - A Look At The New Commandlinefu
I've put together a short writeup on what kind of newness you can expect from the next iteration of clfu. Check it out here.
March 2, 2015 - New Management
I'm Jon, I'll be maintaining and improving clfu. Thanks to David for building such a great resource!

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Psst. Open beta.

Wow, didn't really expect you to read this far down. The latest iteration of the site is in open beta. It's a gentle open beta-- not in prime-time just yet. It's being hosted over at UpGuard (link) and you are more than welcome to give it a shot. Couple things:

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Your feedback is appreciated via the form on the beta page. Thanks! -Jon & CLFU Team

shell function to underline a given string.

Terminal - shell function to underline a given string.
underline() { echo $1; for (( i=0; $i<${#1}; i=$i+1)); do printf "${2:-=}"; done; printf "\n"; }
2010-02-26 05:46:49
User: bartonski
Functions: echo printf
shell function to underline a given string.

underline() will print $1, followed by a series of '=' characters the width of $1. An optional second argument can be used to replace '=' with a given character.

This function is useful for breaking lots of data emitted in a for loop into sections which are easier to parse visually. Let's say that 'xxxx' is a very common pattern occurring in a group of CSV files.

You could run

grep xxxx *.csv

This would print the name of each csv file before each matching line, but the output would be hard to parse visually.

for i in *.csv; do printf "\n"; underline $i; grep "xxxx" $i; done

Will break the output into sections separated by the name of the file, underlined.


There are 2 alternatives - vote for the best!

Terminal - Alternatives

Know a better way?

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What others think

underline() { echo $1; echo "${1//?/${2:-=}}";}


underline() { echo -e "$1\n${1//?/${2:-=}}";}
Comment by mitry 347 weeks and 3 days ago

Nice. I actually thought of this, but couldn't get the substitution to work (now that I re-read the man page, I see that I missed 'If pattern begins with /, all matches of pattern are replaced with string'. I got flummoxed when I found that bash wasn't using a regex match, and stopped reading the man page carefully).

I thought I might be able to shave off an extra character by using

underline() { printf "$1\n${1//?/${2:-=}}";}

but this doesn't put a newline after the underline... ah. I see... that's 'echo -e' which interprets '\n' not 'echo -n' which removes the trailing new line. Thus I could use

underline() { printf "$1\n${1//?/${2:-=}}\n";}

but I'd be a stroke over par.

Comment by bartonski 347 weeks and 2 days ago

or using escape sequences

underline() { echo -e "\E[4m$1\E[0m" }

you can colour it too then...

Comment by quigybo 347 weeks and 2 days ago

Your point of view

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