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Bash function to see what the day ends in

Terminal - Bash function to see what the day ends in
date +%A | cut -c $(( $(date +%A | wc -c) - 1 ))
2010-04-07 00:23:15
User: DaveQB
Functions: cut date wc
0
Bash function to see what the day ends in

A command to find out what the day ends in. Can be edited slightly to find out what "any" output ends in.

NB: I haven't tested with weird and wonderful output.

Alternatives

There is 1 alternative - vote for the best!

Terminal - Alternatives
function ends_in_y() { case $(date +%A) in *y ) true ;; * ) false ;; esac } ; ends_in_y && echo ok
2010-04-06 22:18:52
Functions: date echo false true
-1

The shell has perfectly adequate pattern matching for simple expressions.

function ends_in_y() { if [ `date +%A | sed -e 's/\(^.*\)\(.$\)/\2/'` == "y" ]; then echo 1; else echo 0; fi }
2010-04-06 20:14:34
User: allrightname
Functions: echo sed
-3

For those days when you need to know if something is happening because the day ends in "y".

Know a better way?

If you can do better, submit your command here.

What others think

It's bad form to run a command twice for the same output.

Also you don't need wc, the shell will provide:

D=$(date +%A); cut -c ${#D} <<< $D
Comment by flatcap 237 weeks and 3 days ago

Nice one flatcap, thanks.

I was trying to avoid a VAR for some unkown reason.

Comment by DaveQB 237 weeks and 3 days ago

Your point of view

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