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give record size of given record-structured file

Terminal - give record size of given record-structured file
fname=$1;f=$(ls -la $fname);fsz=$(echo $f|awk '{ print $5 }');nrrec=$(wc -l $fname|awk '{ print $1 }');recsz=$(expr $fsz / $nrrec);echo "$recsz"
2010-09-14 08:40:22
User: vuurst
Functions: awk echo expr ls wc
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give record size of given record-structured file

command was too long...

this is the complete command:

fname=$1; f=$( ls -la $fname ); if [ -n "$f" ]; then fsz=$( echo $f | awk '{ print $5 }' ); if [ "$fsz" -ne "0" ]; then nrrec=$( wc -l $fname | awk '{ print $1 }' ); recsz=$( expr $fsz / $nrrec ); echo "$recsz"; else echo "0"; fi else echo "file $fname does not exist" >&2; fi

First the input is stored in var $fname

The file is checked for existance using "ls -lart".

If the output of "ls -lart" is empty, the error message is given on stderr

Otherwise the filelength is taken from the output of "ls -lart" (5th field)

With "wc -l" the number of records (or lines) is taken.

The record size is filelength devided by the number of records.

please note: this method does not take into account any headers, variable length records and only works on ascii files where the records are sperated by 0x0A (or 0x0A/0x0D on MS-DOS/Windows).

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