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List all execs in $PATH, usefull for grepping the resulting list

Terminal - List all execs in $PATH, usefull for grepping the resulting list
find ${PATH//:/ } -executable -type f -printf "%f\n"
2009-02-16 06:03:46
User: kamathln
Functions: find
5
List all execs in $PATH, usefull for grepping the resulting list

##Dependancies: bash coreutils

Many executables in $PATH have the keyword somewhere other than the beginning in their file names. The command is useful for exploring the executables in $PATH like this.

find ${PATH//:/ } -executable -type f -printf "%f\n" |grep admin

lpadmin

time-admin

network-admin

svnadmin

users-admin

django-admin

shares-admin

services-admin

Alternatives

There are 4 alternatives - vote for the best!

Terminal - Alternatives
find ${PATH//:/ } -iname "*admin*" -executable -type f
2010-03-29 10:20:07
User: sanmiguel
Functions: find
Tags: bash find unix
1

While it seems (to me at least) a little counter-intuitive to filter on name first, this requires less work for find, as it allows it to immediately discount any files that do not match the name directly from the directory listing on disk. Querying against file attributes requires reading the file attributes, which is performed for all files matching any name based predicates.

Know a better way?

If you can do better, submit your command here.

What others think

Hi,

If you would like to negate symlinks then use the -P option. Also, I recommend using -maxdepth 1 to prevent find from traversing into subdirectories. Shells do not traverse the subdirectories found in $PATH. For example, if PATH=/bin:/usr/local/bin and you have a subdirectory inside /usr/local/bin/xyz, the shell will NOT look in the xyz directory for your command thus the find command should do the same.

Example:

find -P ${PATH//:/ } -maxdepth 1 -executable -type f -printf "%f\n" | sort

-GreenEggs

Comment by greeneggs 223 weeks and 5 days ago

Your point of view

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