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Normally, if you just want to see directories you'd use brianmuckian's command 'ls -d *\', but I ran into problems trying to use that command in my script because there are often multiple directories per line. If you need to script something with directories and want to guarantee that there is only one entry per line, this is the fastest way i know
There are 2 alternatives - vote for the best!
Alternatively,
ls -F | grep /\$
but will break on directories containing newlines. Or the safe, POSIX sh way (but will miss dotfiles):
for i in *; do test -d "./$i" && printf "%s\n" "$i"; done
If you can do better, submit your command here.
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yes, I'm commenting on my own script just minutes after posting it, it seems (quite obvious now) that it will only work when there are no spaces in the directory name. there is no easy fix for that without inflating the sed command, perhaps a find command is more efficient
LinuxMan, have you read 'man ls' for obvious parameter 'ls -1'
Also, when 'ls' output is a pipe - it always output in one-column format
Try 's!.*:.. !!' as your expression instead.
here is a zsh command for that, using the extended glob (/)
ls -1d *(/)