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Functions

Returns the absolute path to a command, using which if needed

Terminal - Returns the absolute path to a command, using which if needed
get_absolute_path() { echo $1 | sed "s|^\([^/].*/.*\)|$(pwd)/\1|;s|^\([^/]*\)$|$(which -- $1)|;s|^$|$1|"; }
2011-09-13 11:06:55
User: keymon
Functions: echo sed
-4
Returns the absolute path to a command, using which if needed

It will return the absolute location of the called a script. If is in $PATH, it will search it using which.

You can combine this function with this other one: http://www.commandlinefu.com/commands/view/9252/readlink-equivalent-using-shell-commands-and-following-all-links, to get a way to know where is the real location of a called script:

# Returns the realpath of a called command. whereis_realpath() { local SCRIPT_PATH=$(whereis $1); myreadlink ${SCRIPT_PATH} | sed "s|^\([^/].*\)\$|$(dirname ${SCRIPT_PATH})/\1|"; }

Alternatives

There are 2 alternatives - vote for the best!

Terminal - Alternatives
which any_path/a_command.sh | sed "s|^./|$(pwd)|"
2011-09-22 10:38:56
User: keymon
Functions: sed which
-8

This works in multiple unixes, not only linux, for different paths.

On solaris, if you do not have which, you can use:

ksh whence -p anypath/a_command.sh | sed "s|^./|$(pwd)|" ksh whence -p

Know a better way?

If you can do better, submit your command here.

What others think

I don't get the reason for this... "which" does the exact same here:

ahu:~$ which ls

/bin/ls

or the type command:

ahu:~$ type ls

ls is /bin/ls

Comment by peshay 150 weeks and 1 day ago

`whereis' is already a command:

whereis ls ls: /bin/ls /usr/bin/ls /usr/X11R6/bin/ls /usr/bin/X11/ls /usr/X11/bin/ls /usr/man/man1/ls.1.gz /usr/share/man/man1/ls.1.gz /usr/X11/man/man1/ls.1.gz
Comment by h3xx 150 weeks ago

I changed the function name.

which does the same?

$ touch a_command.sh ; chmod +x a_command.sh

$ which a_command.sh

./a_command.sh

$ type a_command.sh

a_command.sh is ./a_command.sh

I am not getting the absolute path here.

But you are right that you can do:

which a_command.sh | sed "s|^./|$(pwd)|"

Comment by keymon 149 weeks ago

Your point of view

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