Printout a list of field numbers (awk index) from a CSV file with headers as first line.
$ cat file.csv
ID, EMPLOYEE, AGE, SALARY
2,Jack Sparrow,41,10000
3,Mr. Bean,55,12900
15,Kermit the frog,25,29300
$ head -1 file.csv | tr ',' '\n' | tr -d " " | awk '{print NR,$0}'
1 ID
2 EMPLOYEE
3 AGE
4 SALARY
2 Alternatives + Submit Alt
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Take the header line from a comma-delimited CSV file and enumerate the fields. . First sed replaces all commas with newlines
s/,/\n/gThen sed quits (q) after the first line. Finally, nl numbers all the lines Show Sample Output0sed 's/,/\n/g;q' file.csv | nl -
-F, use , as field separator gsub() deletes all spaces for(){} loops over all input fields and print their index and value exit exit after first line Show Sample Output
-2awk -F, '{gsub(/ /,"");for(f=1;f<=NF;f++) print f,$f;exit}' file.csv
What do you think?
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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First Name,Family NameAlso using awk to number lines is a bit heavy, that's what "nl" is for:head -1 file.csv | tr ',' '\n' | nl