list all instances of a file in your PATH directories (without duplicates) in PATH order

function wherepath () { for DIR in `echo $PATH | tr ":" "\n" | awk '!x[$0]++ {print $0}'`; do ls ${DIR}/$1 2>/dev/null; done }
The wherepath function will search all the directories in your PATH and print a unique list of locations in the order they are first found in the PATH. (PATH often has redundant entries.) It will automatically use your 'ls' alias if you have one or you can hardcode your favorite 'ls' options in the function to get a long listing or color output for example. Alternatives: 'whereis' only searches certain fixed locations. 'which -a' searches all the directories in your path but prints duplicates. 'locate' is great but isn't installed everywhere (and it's often too verbose).
Sample Output
$ PATH=/opt/freeware/bin:/usr/bin:/usr/bin:/usr/bin:/usr/local/bin:/usr/sbin:$HOME/bin:/opt/freeware/bin:$HOME/bin

$ wherepath awk
/opt/freeware/bin/awk
/usr/bin/awk
/home/user/bin/awk

0
By: mscar
2010-04-02 20:32:36

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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