Display error pages in report format

sudo awk '($9 ~ /404/)' /var/log/httpd/www.domain-access_log | awk '{print $2,$9,$7,$11}' | sort | uniq -c
This command will return a full list of Error 404 pages in the given access log. The following variables have been given to awk Hostname ($2), ERROR Code ($9), Missing Item ($7), Referrer ($11) You can then send this into a file (>> /path/to/file), which you can open with OpenOffice as a CSV

1
By: ninjasys
2010-04-09 10:31:50

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What Others Think

I love these log processing commands!
AskApache · 427 weeks and 3 days ago
Thank you :)
ninjasys · 427 weeks and 3 days ago
Suggest some minor changes: - Use "$9 ~ /" 404 [-0-9]/ -- if any part of the line has "404" like the referer or user agent, it will be included - Use $1 instead of $2. $2 is the remote name if supplied. I have never seen it supplied. Use the IP address/hostname from field 1 instead. - Combine both awk one-liners into one awk '$9 ~ /" 404 [-0-9]/ { print $1, $9, $7, $11 }' | sort | uniq -c
stanishjohnd · 427 weeks and 2 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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