Octal ls

ls -l | awk '{k=0;for(i=0;i<=8;i++)k+=((substr($1,i+2,1)~/[rwx]/)*2^(8-i));if(k)printf("%0o ",k);print}'
Do ls with permissions written in octal form.
Sample Output
644 -rw-r--r-- 1 iarno users 8947 2008-06-25 10:15 index.html
755 drwxr-xr-x 2 iarno users 4096 2008-06-01 10:31 js

6
By: iArno
2009-02-13 19:20:54

What Others Think

use of command "stat" works too, eg: stat -c%a\ %n * or stat --printf="%a\t%s\t\t%n\t\n" * etc... (man stat for more info) depending on what you exactly want to do...
gniourf_gniourf · 500 weeks and 2 days ago
zsh function ols() { ls $* | awk '{k=0;for(i=0;i }
susannakaukinen · 497 weeks and 3 days ago
you need to change instead of "i+2" "i+1" cuz it does not give good results.
RanyAlbeg · 462 weeks and 3 days ago
im sorry . forget what i said :)
RanyAlbeg · 462 weeks and 3 days ago
Thanks for this! It's pretty much what I wanted! I can always say "I wish I can use this to see my colors in the terminal!" and other stupid bits, but I was able to do this in ~/.bash_profile: alias lo="ls -l | awk '{k=0;for(i=0;i
AboveUnrefined · 343 weeks and 1 day ago
Sorry for the previous, but the escapes added killed my previous comment! In the alias I just enclosed in double quotes and then added escapes as needed, basically before the $ and other double quotes
AboveUnrefined · 343 weeks and 1 day ago
find . -maxdepth 1 -name ".git" -prune -o -printf "%#m %p\n" | sed -r -e "s/^([0-9]+)\\s\\.\\//\\1 /" | sort -k1
Tatsh · 158 weeks and 6 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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