List all execs in $PATH, usefull for grepping the resulting list

find ${PATH//:/ } -executable -type f -printf "%f\n"
##Dependancies: bash coreutils Many executables in $PATH have the keyword somewhere other than the beginning in their file names. The command is useful for exploring the executables in $PATH like this. find ${PATH//:/ } -executable -type f -printf "%f\n" |grep admin lpadmin time-admin network-admin svnadmin users-admin django-admin shares-admin services-admin

5
By: kamathln
2009-02-16 06:03:46

1 Alternatives + Submit Alt

What Others Think

Hi, If you would like to negate symlinks then use the -P option. Also, I recommend using -maxdepth 1 to prevent find from traversing into subdirectories. Shells do not traverse the subdirectories found in $PATH. For example, if PATH=/bin:/usr/local/bin and you have a subdirectory inside /usr/local/bin/xyz, the shell will NOT look in the xyz directory for your command thus the find command should do the same. Example: find -P ${PATH//:/ } -maxdepth 1 -executable -type f -printf "%f\n" | sort -GreenEggs
greeneggs · 321 weeks and 3 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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