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ls output with mode in octal

Terminal - ls output with mode in octal
perl -e 'printf "%o\n", (stat shift)[2]&07777' file
2013-06-15 19:26:23
User: smallduck
Functions: perl stat
ls output with mode in octal


There are 2 alternatives - vote for the best!

Terminal - Alternatives
lso(){ jot -w '%04d' 7778 0000 7777 |sed '/[89]/d;s,.*,printf '"'"'& '"'"';chmod & '"$1"';ls -l '"$1"'|sed s/-/./,' \ |sh \ |{ echo "lso(){";echo "ls \$@ \\";echo " |sed '";sed 's, ,@,2;s,@.*,,;s,\(.* \)\(.*\),s/\2/\1/,;s, ,,';echo \';echo };};}
2012-01-08 05:48:24
User: argv
Functions: chmod echo ls sed sh

this requires the use of a throwaway file.

it outputs a shell function.

assuming the throwaway file is f.tmp

usage: >f.tmp;lso f.tmp > f.tmp; . f.tmp;rm f.tmp;lso -l ...


credit epons.org for the idea. however his version did not account for the sticky bit and other special cases.

many of the 4096 permutations of file permissions make no practical sense. but chmod will still create them.

one can achieve the same sort of octal output with stat(1), if that utility is available.

here's another version to account for systems with seq(1) instead of jot(1):


case $# in


{ case $(uname) in


jot -w '%04d' 7778 0000 7777 ;;


seq -w 0000 7777 ;;

esac; } \

|sed '


s,.*,printf '"'"'& '"'"';chmod & '"$1"';ls -l '"$1"'|sed s/-/./,' \

|sh \


echo "lso(){";

echo "ls \$@ \\";

echo " |sed '";

sed '

s, ,@,2;


s,\(.* \)\(.*\),s/\2/\1/,;

s, ,,';

echo \';

echo };




echo "usage: lso tmp-file";




this won't print out types[1]. but its purpose is not to examine types. its focus is on mode and its purpose is to make mode easier to read (assuming one finds octal easier to read).

1. one could of course argue "everything is a file", but not always a "regular" one. e.g., a "directory" is really just a file comprising a list.

ls -l | sed -e 's/--x/1/g' -e 's/-w-/2/g' -e 's/-wx/3/g' -e 's/r--/4/g' -e 's/r-x/5/g' -e 's/rw-/6/g' -e 's/rwx/7/g' -e 's/---/0/g'

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Comment by femalemalls11 119 weeks and 5 days ago

Your point of view

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