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Functions

A function to find the newest file in a directory

Terminal - A function to find the newest file in a directory
newest () { find ${1:-\.} -type f |xargs ls -lrt ; }
2010-02-04 14:52:17
User: mobidyc
Functions: find ls xargs
5
A function to find the newest file in a directory

Alternatives

There are 3 alternatives - vote for the best!

Terminal - Alternatives
newest () { candidate=''; for i in "$@"; do [[ -f $i ]] || continue; [[ -z $candidate || $i -nt $candidate ]] && candidate="$i"; done; echo "$candidate"; }
2009-10-29 17:35:01
User: johnraff
Functions: echo
Tags: bash files
1

Usage example:

newest Desktop/*

Replace "-nt" with "-ot" for oldest.

Run

shopt -s dotglob

first to include dotfiles.

newest () { DIR=${1:-'.'}; CANDIDATE=`find $DIR -type f|head -n1`; while [[ ! -z $CANDIDATE ]]; do BEST=$CANDIDATE; CANDIDATE=`find $DIR -newer "$BEST" -type f|head -n1`; done; echo "$BEST"; }
2010-02-04 12:40:44
User: shadycraig
Functions: echo head
1

Works recusivley in the specified dir or '.' if none given.

Repeatedly calls 'find' to find a newer file, when no newer files exist you have the newest.

In this case 'newest' means most recently modified. To find the most recently created change -newer to -cnewer.

find /path/to/dir -type f -printf "%T@|%p\n" 2>/dev/null | sort -n | tail -n 1| awk -F\| '{print $2}'

Know a better way?

If you can do better, submit your command here.

What others think

I gave my vote to this one:

newest () { find ${1:-\.} -type f |xargs ls -lrt ; }

But I have to ask, why write a function for this when a simple $(ls -ltr) would do? Then again, are we assuming the last file that was modified in that directory wasn't a .file? Then we should do $(ls -altr). My $0.02.

Comment by unixhome 29 weeks and 3 days ago

I forgot to mention that this function is better for recursive use.

dis you ever try an

ls -lrtR

ls is not not efficiently for this.

Comment by mobidyc 24 weeks and 6 days ago

Your point of view

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