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Most systems (at least my macbook) have system users defined, such as _www and using "users" for example will not list them. This command allows you to see who the 'virtual' users are on your system.
There is 1 alternative - vote for the best!
Shows a list of users that currently running processes are executing as.
YMMV regarding ps and it's many variants. For example, you might need:
ps -axgu | cut -f1 -d' ' | sort -u
If you can do better, submit your command here.
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Interesting. What is this supposed to do?
sudo lsof|sed 's/ */ /g'|cut -f3 -d' '|sort -ua
b
c
d
e
h
i
j
l
m
n
o
O
p
r
s
t
u
v
I think you need to put TWO spaces in sed pattern (maybe you do, but it's hard to see). When I do that, I get something like this:
sudo lsof|sed 's/ */ /g'|cut -f3 -d' '|sort -uUSER
_coreaudiod
_mdnsresponder
_spotlight
_usbmuxd
_windowserver
daemon
george
root
I think tr -s instead of the sed:
sudo lsof | tr -s ' ' | cut -f3 -d' ' | sort -ubut I think ps can do this too. I'll post an alternative...
If you want to collapse spaces in sed you should use the "one or more" repetition rather than "zero or more"
sed 's/ \+/ /g'but what you're looking for, instead, is awk:
sudo lsof | awk '{ print $3 }' | sort -u