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Shows users and 'virtual users' on your a unix-type system

Terminal - Shows users and 'virtual users' on your a unix-type system
sudo lsof|sed 's/ */ /g'|cut -f3 -d' '|sort -u
2010-07-07 08:20:28
User: binaryten
Functions: cut sed sort sudo
-4
Shows users and 'virtual users' on your a unix-type system

Most systems (at least my macbook) have system users defined, such as _www and using "users" for example will not list them. This command allows you to see who the 'virtual' users are on your system.

Alternatives

There are 4 alternatives - vote for the best!

Terminal - Alternatives
ps -eo user | sort -u
2010-07-07 12:28:44
User: dfaulkner
Functions: ps sort
2

Shows a list of users that currently running processes are executing as.

YMMV regarding ps and it's many variants. For example, you might need:

ps -axgu | cut -f1 -d' ' | sort -u
cut -d: -f1 /etc/passwd | sort
ps -axgu | cut -f1 -d' ' | sort -u

Know a better way?

If you can do better, submit your command here.

What others think

Interesting. What is this supposed to do?

sudo lsof|sed 's/ */ /g'|cut -f3 -d' '|sort -u

a

b

c

d

e

h

i

j

l

m

n

o

O

p

r

s

t

u

v

Comment by OJM 255 weeks and 3 days ago

I think you need to put TWO spaces in sed pattern (maybe you do, but it's hard to see). When I do that, I get something like this:

sudo lsof|sed 's/ */ /g'|cut -f3 -d' '|sort -u

USER

_coreaudiod

_mdnsresponder

_spotlight

_usbmuxd

_windowserver

daemon

george

root

Comment by zabouti 255 weeks and 3 days ago

I think tr -s instead of the sed:

sudo lsof | tr -s ' ' | cut -f3 -d' ' | sort -u

but I think ps can do this too. I'll post an alternative...

Comment by dfaulkner 255 weeks and 3 days ago

If you want to collapse spaces in sed you should use the "one or more" repetition rather than "zero or more"

sed 's/ \+/ /g'

but what you're looking for, instead, is awk:

sudo lsof | awk '{ print $3 }' | sort -u
Comment by Flameeyes 255 weeks and 3 days ago

Your point of view

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