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Takes a random number modulo the number of files in $dir, prints the filename corresponding to that number, and passes it as an argument to man.
There are 4 alternatives - vote for the best!
I'm not sure why you would want to do this, but this seems a lot simpler (easier to understand) than the version someone submitted using awk.
Great idea camocrazed. Another twist would be to display a different man page based on the day of the year. The following will continuously cycle through all man pages:
man $(ls /bin | sed -n $(($(date +%j) % $(ls /bin | wc -l)))p)
Maybe not the quicker because of the sort command, but it will also look in other man sections.
updated with goodevilgenius 'shuf' idea
Build an awk array with all commands and then select a random one at the end.
This avoids spawning extra processes for counting with wc or generating random numbers.
Explicitly call /bin/ls to avoid interactions with aliases.
If you can do better, submit your command here.
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