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ls not pattern
I've been looking for a way to do this for a while, get a not pattern for shell globs. This works, I'm using to grab logs from a remote server via scp.

Convert control codes to visible Unicode Control Pictures
Converts control codes and spaces (ASCII code ≤ 32) to visible Unicode Control Pictures, U+2400 ? U+2420. Skips \n characters, which is probably a good thing.

Convert seconds to [DD:][HH:]MM:SS
Converts any number of seconds into days, hours, minutes and seconds. sec2dhms() { declare -i SS="$1" D=$(( SS / 86400 )) H=$(( SS % 86400 / 3600 )) M=$(( SS % 3600 / 60 )) S=$(( SS % 60 )) [ "$D" -gt 0 ] && echo -n "${D}:" [ "$H" -gt 0 ] && printf "%02g:" "$H" printf "%02g:%02g\n" "$M" "$S" }

Print all the lines between 10 and 20 of a file
Subtly different to the -n+p method... and probably wrong in so many ways....... But it's shorter. Just.

Install pip with Proxy
Installs pip packages defining a proxy

Which processes are listening on a specific port (e.g. port 80)
swap out "80" for your port of interest. Can use port number or named ports e.g. "http"

How to estimate the storage size of all files not named *.[extension] on the current directory
With this sentence we can estimate the storage size of all files not named *.jpg on the current directory. The syntax is based on Linux, for Unix compliance use: find ./* -prune ! -name '*.jpg' -ls |awk '{TOTAL+=$7} END {print int(TOTAL/(1024^2))"MB"}' We can change the jpg extension for whatever extension what we need

Create a large test file (taking no space).

Which processes are listening on a specific port (e.g. port 80)
swap out "80" for your port of interest. Can use port number or named ports e.g. "http"

Create a new file


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