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Use the -a flag to display all files, including hidden files. If you just want to display regular files, use a -1 (yes, that is the number one). Got this by RTFM and adding some sed magic.
[bbbco@bbbco-dt ~]$ ls -a | sed "s#^#${PWD}/#"
/home/bbbco/.
/home/bbbco/..
/home/bbbco/2011-09-01-00-33-02.073-VirtualBox-2934.log
/home/bbbco/2011-09-10-09-49-57.004-VirtualBox-2716.log
/home/bbbco/.adobe
/home/bbbco/.bash_history
/home/bbbco/.bash_logout
/home/bbbco/.bash_profile
/home/bbbco/.bashrc
...
[bbbco@bbbco-dt ~]$ ls -1 | sed "s#^#${PWD}/#"
/home/bbbco/2011-09-01-00-33-02.073-VirtualBox-2934.log
/home/bbbco/2011-09-10-09-49-57.004-VirtualBox-2716.log
/home/bbbco/cookies.txt
/home/bbbco/Desktop
/home/bbbco/Documents
/home/bbbco/Downloads
...
There is 1 alternative - vote for the best!
List the full path of some files.
You can add ".*" on the end if you want to display hidden files.
If you can do better, submit your command here.
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Not exactly command line material, but this inspired me to try to learn some more C. (on my general to-do list) So thought I would share:
#include
#include
#include
#include
int main(){
DIR* dir = opendir(".");
struct dirent* entry;
char cwd[4096];
getcwd(cwd, 4096);
while ( (entry = readdir(dir))) {
printf("%s/%s\n", cwd, entry->d_name);
}
}
well that didn't format as i had hoped :)