List all groups and the user names that were in each group

for u in `cut -f1 -d: /etc/passwd`; do echo -n $u:; groups $u; done | sort
"cut" the user names from /etc/passwd and then running a loop over them.
Sample Output
avahi-autoipd:avahi-autoipd
avahi:avahi
backup:backup
bin:bin
daemon:daemon
debian-tor:debian-tor
debian-transmission:debian-transmission
games:games
gdm:gdm
gnats:gnats
haldaemon:haldaemon

3
By: hemanth
2009-08-22 09:06:02

1 Alternatives + Submit Alt

What Others Think

Glad you're enjoying our blog. In future, however, it would be nice if you gave some attribution when you're posting our content here on commandlinefu. This one is from http://blog.commandlinekungfu.com/2009/06/episode-44-users-groups-part-ii.html By the way, this command lists all groups that each user is a member of, not the users in each group. For the latter answer, see http://blog.commandlinekungfu.com/2009/06/episode-43-users-groups.html
Hal_Pomeranz · 464 weeks ago
it's shorter in my fedora: for u in `cut -f1 -d: /etc/passwd`; do groups $u; done | sort
Charon · 463 weeks and 5 days ago

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