List all groups and the user names that were in each group

for u in `cut -f1 -d: /etc/passwd`; do echo -n $u:; groups $u; done | sort
"cut" the user names from /etc/passwd and then running a loop over them.
Sample Output

By: hemanth
2009-08-22 09:06:02

1 Alternatives + Submit Alt

What Others Think

Glad you're enjoying our blog. In future, however, it would be nice if you gave some attribution when you're posting our content here on commandlinefu. This one is from By the way, this command lists all groups that each user is a member of, not the users in each group. For the latter answer, see
Hal_Pomeranz · 677 weeks ago
it's shorter in my fedora: for u in `cut -f1 -d: /etc/passwd`; do groups $u; done | sort
Charon · 676 weeks and 6 days ago
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kyliesmith · 36 weeks and 5 days ago
avideh · 25 weeks and 5 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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