sort the output of the 'du' command by largest first, using human readable output.

du -h --max-depth=1 |sort -rh
In this case I'm just grabbing the next level of subdirectories (and same level regular files) with the --max-depth=1 flag. leaving out that flag will just give you finer resolution. Note that you have to use the -h switch with both 'du' and with 'sort.'
Sample Output
$ du -h --max-depth=1 |sort -rh
4.7M	.
4.3M	./locales
120K	./initializers
112K	./.svn
112K	./environments

14
By: jambino
2011-11-15 20:30:00

What Others Think

Doesn't seem to work on a linux systems, atleast not on rhel
pykler · 514 weeks ago
Doesn't seem to work on a linux systems, atleast not on rhel
pykler · 514 weeks ago
The -h option to sort is a new one. RHEL 5 does not have that version of sort. You can grab the sort command from a more recent Linux distro and use. I have done that.
DaveQB · 514 weeks ago
Short form of this command would be: du -sh * | sort -rh
sirex · 514 weeks ago
For older versions of sort this should to the trick: du --max-depth=1 | sort -nr | awk '{suffs="k M G"; N=split(suffs,suff," "); for(n=1; $1>1024 && n<N; n=n+1) {$1=$1/1024} printf("%0.1f%s\t%s\n", $1, suff[n], $2)}'
aikikode · 513 weeks and 6 days ago
Yeah, I'm finding that EL 5 (RHEL, CentOS, SL, RedHawk) has an earlier version of sort that doesn't have the '-h' switch. I'm going through some of my older boxes and upgrading sort just to have this. I use it too much not to have it available.
jambino · 513 weeks and 6 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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