Commands using du (244)
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51du -s * | sort -n | tail
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Probably only works with GNU du and modern perls. Show Sample Output
36du -b --max-depth 1 | sort -nr | perl -pe 's{([0-9]+)}{sprintf "%.1f%s", $1>=2**30? ($1/2**30, "G"): $1>=2**20? ($1/2**20, "M"): $1>=2**10? ($1/2**10, "K"): ($1, "")}e' -
What happens here is we tell tar to create "-c" an archive of all files in current dir "." (recursively) and output the data to stdout "-f -". Next we specify the size "-s" to pv of all files in current dir. The "du -sb . | awk ?{print $1}?" returns number of bytes in current dir, and it gets fed as "-s" parameter to pv. Next we gzip the whole content and output the result to out.tgz file. This way "pv" knows how much data is still left to be processed and shows us that it will take yet another 4 mins 49 secs to finish. Credit: Peteris Krumins http://www.catonmat.net/blog/unix-utilities-pipe-viewer/ Show Sample Output
27tar -cf - . | pv -s $(du -sb . | awk '{print $1}') | gzip > out.tgz -
17du -h /path | sort -h
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I use this on debian testing, works like the other sorted du variants, but i like small numbers and suffixes :) Show Sample Output
16du --max-depth=1 | sort -r -n | awk '{split("k m g",v); s=1; while($1>1024){$1/=1024; s++} print int($1)" "v[s]"\t"$2}' -
Directories listed in human-readable format
16du -hs */ | sort -hr | head -
In this case I'm just grabbing the next level of subdirectories (and same level regular files) with the --max-depth=1 flag. leaving out that flag will just give you finer resolution. Note that you have to use the -h switch with both 'du' and with 'sort.' Show Sample Output
14du -h --max-depth=1 |sort -rh -
i'm using gawk, you may get varying mileage with other varieties. You might want to change the / after du to say, /home/ or /var or something, otherwise this command might take quite some time to complete. Sorry it's so obsfucated, I had to turn a script into a one-liner under 255 characters for commandlinefu. Note: the bar ratio is relative, so the highest ratio of the total disk, "anchors" the rest of the graph. EDIT: the math was slightly wrong, fixed it. Also, made it compliant with older versions of df. Show Sample Output
13t=$(df|awk 'NR!=1{sum+=$2}END{print sum}');sudo du / --max-depth=1|sed '$d'|sort -rn -k1 | awk -v t=$t 'OFMT="%d" {M=64; for (a=0;a<$1;a++){if (a>c){c=a}}br=a/c;b=M*br;for(x=0;x<b;x++){printf "\033[1;31m" "|" "\033[0m"}print " "$2" "(a/t*100)"% total"}' -
A more efficient way, with reversed order to put the focus in the big ones. Show Sample Output
12du -x --max-depth=1|sort -rn|awk -F / -v c=$COLUMNS 'NR==1{t=$1} NR>1{r=int($1/t*c+.5); b="\033[1;31m"; for (i=0; i<r; i++) b=b"#"; printf " %5.2f%% %s\033[0m %s\n", $1/t*100, b, $2}'|tac -
Use this as a quick and simple alternative to the slightly verbose "du -s --max-depth=1" Show Sample Output
11du -sh * -
Very useful when you need disk space. It calculates the disk usage of all files and dirs (descending them) located at the current directory (including hidden ones). Then sort puts them in order.
11du -cs * .[^\.]* | sort -n -
Search for files and list the 20 largest.
find . -type fgives us a list of file, recursively, starting from here (.)-print0 | xargs -0 du -hseparate the names of files with NULL characters, so we're not confused by spaces then xargs run the du command to find their size (in human-readable form -- 64M not 64123456)| sort -hruse sort to arrange the list in size order. sort -h knows that 1M is bigger than 9K| head -20finally only select the top twenty out of the list Show Sample Output11find . -type f -print0 | xargs -0 du -h | sort -hr | head -20 -
10find . -size +100000k -exec du -h {} \;
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9du -sk * |sort -rn |head
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use "watch" instead of while-loops in these simple cases
9watch -n60 du /var/log/messages -
9find . -type f -print0 | xargs -0 du -h | sort -hr | head -10
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8du -k | sort -r -n | more
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8du -cks * | sort -rn | while read size fname; do for unit in k M G T P E Z Y; do if [ $size -lt 1024 ]; then echo -e "${size}${unit}\t${fname}"; break; fi; size=$((size/1024)); done; done
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why make it complicated ? : ] -------------------- I just noticed someone else has posted this on this site before me (sorry I am now a duplicate :/) http://www.commandlinefu.com/commands/view/4313
8du -hs */ -
This command will tell you the 20 biggest directories starting from your working directory and skips directories on other filesystems. Useful for resolving disk space issues.
7du -xk | sort -n | tail -20 -
7du --max-depth=1
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This allows the output to be sorted from largest to smallest in human readable format.
7sudo du -ks $(ls -d */) | sort -nr | cut -f2 | xargs -d '\n' du -sh 2> /dev/null -
7du -sh */
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Recursively searches current directory and outputs sorted list of each directory's disk usage to a text file. Show Sample Output
6du | sort -gr > file_sizes -
Finds all directories containing more than 99MB of files, and prints them in human readable format. The directories sizes do not include their subdirectories, so it is very useful for finding any single directory with a lot of large files. Show Sample Output
6du -hS / | perl -ne '(m/\d{3,}M\s+\S/ || m/G\s+\S/) && print' - 1 2 3 > Last ›
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