Useful if you don't have at hand the ability to automatically create a booklet, but still want to. F is the number of pages to print. It *must* be a multiple of 4; append extra blank pages if needed. In evince, these are the steps to print it, adapted from https://help.gnome.org/users/evince/stable/duplex-npage.html.en : 1) Click File ▸ Print. 2) Choose the General tab. Under Range, choose Pages. Type the numbers of the pages in this order (this is what this one-liner does for you): n, 1, 2, n-1, n-2, 3, 4, n-3, n-4, 5, 6, n-5, n-6, 7, 8, n-7, n-8, 9, 10, n-9, n-10, 11, 12, n-11... ...until you have typed n-number of pages. 3) Choose the Page Setup tab. - Assuming a duplex printer: Under Layout, in the Two-side menu, select Short Edge (Flip). - If you can only print on one side, you have to print twice, one for the odd pages and one for the even pages. In the Pages per side option, select 2. In the Page ordering menu, select Left to right. 4) Click Print. Show Sample Output
Simply change the years listed in the first seq, and it will print out all the months in that span of years that have Friday the 13ths in them. Show Sample Output
This is a slightly modified version of the knoppix5 user oneliner (https://www.commandlinefu.com/commands/view/24571/draw-line-separator). Show Sample Output
Using perl in a one-liner is a bit overkill to randomly sort some input. `sort` from coreutils should be enough.
https://wuseman.nr1.nu:8080/file/E8AcLVgMPZ2LSJQf/9BD8V8ADYNhR6cca/parallel_print_progress.gif Show Sample Output
Old cron doesn't allow periods
this is very useful when there is a different network host to determine which are turned on or not Show Sample Output
Strangely enough, there is no option --lines=[negative] with tail, like the head's one, so we have to use sed, which is very short and clear, you see. Strangely more enough, skipping lines at the bottom with sed is not short nor clear. From Sed one liner : # delete the last 10 lines of a file $ sed -e :a -e '$d;N;2,10ba' -e 'P;D' # method 1 $ sed -n -e :a -e '1,10!{P;N;D;};N;ba' # method 2 Show Sample Output
Nice command to create a list, you can create too with for command, but this is so faster. Show Sample Output
uses the previous "chr" function and uses it to create the inverse function "ord" by brute force. It's slow, It's inelegant, but it works. I thought I needed ord/chr to do a cartesian cipher in shell script a whie ago, but eventualy I realized I could get fancy with tr and do the same thing...
If you want a sequence that can be plotted, do: seq 8 | awk '{print "e(" $0 ")" }' | bc -l | awk '{print NR " " $0}' Other bc functions include s (sine), c (cosine), l (log) and j (bessel). See the man page for details. Show Sample Output
Calculate pi from the infinite series 4/1 - 4/3 + 4/5 - 4/7 + ... This expansion was formulated by Gottfried Leibniz: http://en.wikipedia.org/wiki/Leibniz_formula_for_pi I helped rubenmoran create the sum of a sequence of numbers and he replied with a command for the sequence: 1 + 2 -3 + 4 ... This set me thinking. Transcendental numbers! seq provides the odd numbers 1, 3, 5 sed turns them into 4/1 4/3 4/5 paste inserts - and + bc -l does the calculation Note: 100 million iterations takes quite a while. 1 billion and I run out of memory. Show Sample Output
seq 20 | awk '{line=line sep $0; sep=" "} !(NR%5){print line; line=sep=""}' Show Sample Output
Can't print correctly in the command field.
There is a new line before } as follows
seq 20 | sed -n '5,6 { w out.txt
}'
Show Sample Output
Search in decimal rather than hex. od dumps the character list, cut to remove offsets, sort -u gives the used characters. seq gives the comparison list, but we need this sorted alphabetically for comm, which does the filtering. I drop to perl to convert back to characters (is there a better way?) and then use od to dump them in a print-safe format. Show Sample Output
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