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May 19, 2015 - A Look At The New Commandlinefu
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Commands tagged cal from sorted by
Terminal - Commands tagged cal - 5 results
YYYY=2014; MM=02; for d in $(cal $MM $YYYY | grep "^ *[0-9]"); do DD=$(printf "%02d" $d); echo $YYYY$MM$DD; done
2014-02-06 11:31:57
User: fibo
Functions: cal echo grep printf
Tags: cal for loop
1

Edit YYYY and MM at the beginning of the command with the year and month you want.

Note that `DD=$(printf "%02d" $d)` will pad single digit integers with a leading zero.

Substitute `echo $YYYY$MM$DD` at the end of the line with the command you want to launch, for instance

script.pl --yyyymmdd $YYYY$MM$DD

for y in {2009..2013}; do cal $y; done
cal 04 2012 | awk '{ $7 && X=$7 } END { print X }'
2012-05-06 23:43:21
User: flatcap
Functions: awk cal
2

If your locale has Monday as the first day of the week, like mine in the UK, change the two $7 into $6

cal 04 2012 | awk 'NF <= 7 { print $7 }' | grep -v "^$" | tail -1
2012-05-03 16:57:45
User: javidjamae
Functions: awk cal grep tail
-2

This is a little trickier than finding the last Sunday, because you know the last Sunday is in the first position of the last line. The trick is to use the NF less than or equal to 7 so it picks up all the lines then grep out any empty lines.

for y in $(seq 2009 2011); do cal $y; done
2009-07-10 10:07:46
Functions: cal seq
Tags: bash seq cal
3

print multiple increasing years using cal - calendar -. You can also try

seq Start Increment End