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Enhanced version: fixes sorting by human readable numbers, and filters out non MB or GB entries that have a G or an M in their name.
Show sizes of all files and directories in a directory in size order.
du -hs * | sort -hr
for reverse order.
You can simply run "largest", and list the top 10 files/directories in ./, or you can pass two parameters, the first being the directory, the 2nd being the limit of files to display.
Best off putting this in your bashrc or bash_profile file
Lists the size in human readable form and lists the top 25 biggest directories/files
Also shows files as they are found. Only works from a tty.
In OSX you would have to make sure that you "sudo -s" your way to happiness since it will give a few "Permission denied" errors before finally spitting out the results. In OSX the directory structure has to start with the "Users" Directory then it will recursively perform the operation.
Your Lord and master,
the -h option of du and sort (on appropriate distrib) makes output "Human" readable and still sorted by "reversed size" (sort -rh)
This command give a human readable result without messing up the sorting.
I had the problem that our monitoring showed that the "/" filesystem is >90% full. This command helped me to find out fast which subdirs are the biggest. The system has many NFS-mounts therefore the -x.
Search for files and list the 20 largest.
find . -type f
gives us a list of file, recursively, starting from here (.)
-print0 | xargs -0 du -h
separate the names of files with NULL characters, so we're not confused by spaces
then xargs run the du command to find their size (in human-readable form -- 64M not 64123456)
| sort -hr
use sort to arrange the list in size order. sort -h knows that 1M is bigger than 9K
| head -20
finally only select the top twenty out of the list