100 .txt 25 .tar.gz 10 .vim 3 .gitignore
... plus do a sort according frequency Show Sample Output
Works on current directory, with built-in sorting. Show Sample Output
Just a little simplification.
If your grep doesn't have an -o option, you can use sed instead.
A shorter version Show Sample Output
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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ls -R1A /some/path | grep -o '\..\+$' | sort | uniq -c | sort -rn
But this looks still ugly...sort | uniq -c | sort -rn
Isn't there a nicer way?