I find the ouput of ls -lR to be un-satisfying (why is the path data up there?) and find syntax to be awkward. Running 'du -a' means you will have likely to trim-off filesize data before feeding filenames to the next step in the pipe.

Remove all zero size files from current directory. Its a not recursive option like: find . -size 0c -exec rm {} \;

Use the -a flag to display all files, including hidden files. If you just want to display regular files, use a -1 (yes, that is the number one). Got this by RTFM and adding some sed magic. [bbbco@bbbco-dt ~]$ ls -a | sed "s#^#${PWD}/#" /home/bbbco/. /home/bbbco/.. /home/bbbco/2011-09-01-00-33-02.073-VirtualBox-2934.log /home/bbbco/2011-09-10-09-49-57.004-VirtualBox-2716.log /home/bbbco/.adobe /home/bbbco/.bash_history /home/bbbco/.bash_logout /home/bbbco/.bash_profile /home/bbbco/.bashrc ... [bbbco@bbbco-dt ~]$ ls -1 | sed "s#^#${PWD}/#" /home/bbbco/2011-09-01-00-33-02.073-VirtualBox-2934.log /home/bbbco/2011-09-10-09-49-57.004-VirtualBox-2716.log /home/bbbco/cookies.txt /home/bbbco/Desktop /home/bbbco/Documents /home/bbbco/Downloads ... Show Sample Output

gunzip all .gz file in current dir

Normally, if you just want to see directories you'd use brianmuckian's command 'ls -d *\', but I ran into problems trying to use that command in my script because there are often multiple directories per line. If you need to script something with directories and want to guarantee that there is only one entry per line, this is the fastest way i know Show Sample Output

it does provide much more information , the owner , group , the size in byte , and the last modified time a file or directory was ls -al : list all in long format Show Sample Output

This command will delete all files and folders except 'skipme'. it could be a file or a folder.

It will list all files in your home directory even if your current directory is not home directory Show Sample Output

ghgh rty uty tr uyuyuyu