Commands using ls

Returns the most recently modified file in the current (or specified) directory. You can also get the oldest file, via:

ls -t1 $* | tail-1 ;

This command does a basic find with size. It also improves the printout given (more clearer then default)

Adjusting the ./ will alter the path.

Adjusting the "-size +100000k" will specify the size to search for.

This will quickly display files last changed in a directory, with the newest on top.

this requires the use of a throwaway file.

it outputs a shell function.

assuming the throwaway file is f.tmp

usage: >f.tmp;lso f.tmp > f.tmp; . f.tmp;rm f.tmp;lso -l ...

notes:

credit epons.org for the idea. however his version did not account for the sticky bit and other special cases.

many of the 4096 permutations of file permissions make no practical sense. but chmod will still create them.

one can achieve the same sort of octal output with stat(1), if that utility is available.

here's another version to account for systems with seq(1) instead of jot(1):

lso(){

case $# in

1)

{ case $(uname) in

FreeBSD)

jot -w '%04d' 7778 0000 7777 ;;

*)

seq -w 0000 7777 ;;

esac; } \

|sed '

/[89]/d

s,.*,printf '"'"'& '"'"';chmod & '"$1"';ls -l '"$1"'|sed s/-/./,' \

|sh \

|{

echo "lso(){";

echo "ls \$@ \\";

echo " |sed '";

sed '

s, ,@,2;

s,@.*,,;

s,\(.* \)\(.*\),s/\2/\1/,;

s, ,,';

echo \';

echo };

};

;;

*)

echo "usage: lso tmp-file";

;;

esac;

}

this won't print out types[1]. but its purpose is not to examine types. its focus is on mode and its purpose is to make mode easier to read (assuming one finds octal easier to read).

1. one could of course argue "everything is a file", but not always a "regular" one. e.g., a "directory" is really just a file comprising a list.

view does not enable the buffer because it opens in read-only, so it does the same

Use the -a flag to display all files, including hidden files. If you just want to display regular files, use a -1 (yes, that is the number one). Got this by RTFM and adding some sed magic.

[bbbco@bbbco-dt ~]$ ls -a | sed "s#^#${PWD}/#"

/home/bbbco/.

/home/bbbco/..

/home/bbbco/2011-09-01-00-33-02.073-VirtualBox-2934.log

/home/bbbco/2011-09-10-09-49-57.004-VirtualBox-2716.log

/home/bbbco/.adobe

/home/bbbco/.bash_history

/home/bbbco/.bash_logout

/home/bbbco/.bash_profile

/home/bbbco/.bashrc

...

[bbbco@bbbco-dt ~]$ ls -1 | sed "s#^#${PWD}/#"

/home/bbbco/2011-09-01-00-33-02.073-VirtualBox-2934.log

/home/bbbco/2011-09-10-09-49-57.004-VirtualBox-2716.log

/home/bbbco/cookies.txt

/home/bbbco/Desktop

/home/bbbco/Documents

/home/bbbco/Downloads

...

This will list the files in a directory, then zip each one with the original filename individually.

video1.wmv -> video1.zip

video2.wmv -> video2.zip

This was for zipping up large amounts of video files for upload on a Windows machine.

Like normal ls, but only lists directories.

Can be used with -l to get more details (ls -lad */)

Will use variable value (for variable $my_dir, in this case), an assign a default value if there is none.

You need to have figlet(for font) and cowsay installed then add it to your .bashrc file.You can see it every time after start a new session.

I simply find binary notation more straightforward to use than octal in this case.

Obviously it is overkill if you just 600 or 700 all of your files...

whereis (1) - locate the binary, source, and manual page files for a command

Not actually better, just expanded a bit. The "whereis" command has the following output:

whereis gcc

gcc: /usr/bin/gcc /usr/lib/gcc /usr/bin/X11/gcc /usr/share/man/man1/gcc.1.gz

therefore the 'ls' error on first line, which could be eliminated with a little extra work.

this is the much easier zsh equivalent ...

List all files in a directory in reverse order by modified timestamp. When piped through tail the user will see the most recent file name.

wrap it in a function if you like...