man $(ls /bin | sed -n $(($(date +%j) % $(ls /bin | wc -l)))p)
I'm not sure why you would want to do this, but this seems a lot simpler (easier to understand) than the version someone submitted using awk.
Broaden your knowledge of the utilities available to you in no particular order whatsoever! Then use that knowledge to create more nifty one-liners that you can post here. =p Takes a random number modulo the number of files in $dir, prints the filename corresponding to that number, and passes it as an argument to man.
Another one. Maybe not the quicker because of the sort command, but it will also look in other man sections. updated with goodevilgenius 'shuf' idea
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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