Commands using sort (800)
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0ac -p | sort -nk 2 | awk '/total/{print x};{x=$1}'
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Prevents the need for the grep & awk statements. Sort is optional if you don't care about the output order. The network range can also be specified as in the original post. -A Display targets by address rather than DNS name. (Probably unnecessary...) -a Show systems that are alive. S fping -r1 -ag 192.168.nnn.0/24 2>/dev/null Without sorting... Show Sample Output
0fping -r1 -Aag <network>/<cidr_mask> 2>/dev/null | sort -gt. -k4 -
0mysql -u root -p -N -e"show processlist\G;" | egrep "Host\:" | awk -F: '{ print $2 }' | sort | uniq -c
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Tested in bash on AIX & Linux, used for WAS versions 6.0 & up. Sorts by node name. Useful when you have vertically-stacked instances of WAS/Portal. Cuts out all the classpath/optional parameter clutter that makes a simple "ps -ef | grep java" so difficult to sort through. Show Sample Output
0ps -ef | grep [j]ava | awk -F ' ' ' { print $1," ",$2,"\t",$(NF-2),"\t",$(NF-1),"\t",$NF } ' | sort -k4 -
Search in decimal rather than hex. od dumps the character list, cut to remove offsets, sort -u gives the used characters. seq gives the comparison list, but we need this sorted alphabetically for comm, which does the filtering. I drop to perl to convert back to characters (is there a better way?) and then use od to dump them in a print-safe format. Show Sample Output
0comm -13 <(od -vw1 -tu1 dummy.txt|cut -c9-|sort -u) <(seq 0 127|sort)|perl -pe '$_=chr($_)'|od -c -
Detect duplicate UID in you /etc/passwd (or GID in /etc/group file). Duplicate UID is often forbidden for it can be a security breach. Show Sample Output
0awk -F: '{print $3}' /etc/passwd | sort |uniq -d -
See who is using a specific port. Especially when you're using AIX. In Ubuntu, for example, this can easily be seen with the netstat command. Show Sample Output
0netstat -Aan | grep .80 | grep -v 127.0.0.1 | grep EST | awk '{print $6}' | cut -d "." -f1,2,3,4 | sort | uniq -
0find . -size +10240k -exec stat -c%s" "%n {} \; | sort -rn
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useful to count events in logs Show Sample Output
0cat z.log | grep Timeout | cut -d ':' -f1 | sort | uniq -c -
useful to count events in logs @see: http://www.commandlinefu.com/commands/view/10327/report-summary-of-string-occurrence-by-time-period-hour#comment Show Sample Output
0cat z.log | cut -d ':' -f1 | sort | uniq | xargs -l1 -iFF echo 'echo FF $(cat z.log | grep -e "^FF" | grep -e Timeout | wc -l )' | bash -
This let me find some a set of modifications that were made to a rather large tree of files, where the file-names themselves were not unique (actually: insanely redundant and useless. "1.dat 2.dat ..."). Pruning down to last-branch brough things back to the "project-name" scope, and it's then easy to see which branches of the tree have recently changed, or any other similar search. Ideally, it should sort the directories by the mtime of the most recent *file* *inside* the directory, but that's probably outside the scope of a (sane...) command line.
0ls -ltr --directory $(find . -regex "./.*[^/]*\'" -type f | xargs -n 1 dirname | sort | uniq) -
0head -n1 nation.tbl | sed 's/\(.\)/\1\n/g' | sort | uniq -c | grep \| | awk '{ print $1 }'
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optionally you can add
|cut -d' ' -f2|uniqto the end of the command line.0for a in $(cat sample.txt); do echo "$(wc -m<<<$a) $a";done|sort -n -
0du -s $(ls -l | grep '^d' | awk '{print $9}') | sort -nr
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0for a in $(cat sample.txt); do echo "${#a} $a";done|sort -n
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Take a file and ,."()?!;: give a list of all the words in order of increasing length. First of all use tr to map all alphabetic characters to lower case and also strip out any puntuation. A-Z become a-z ,."()?!;: all become \n (newline) I've ignored - (hyphen) and ' (apostrophe) because they occur in words. Next use bash to print the length ${#w} and the word Finally sort the list numerically (sort -n) and remove any duplicates (sort -u). Note: sort -nu performs strangely on this list. It outputs one word per length. Show Sample Output
0for w in $(tr 'A-Z ,."()?!;:' 'a-z\n' < sample.txt); do echo ${#w} $w; done | sort -u | sort -n -
0for a in $(< FILENAME); do echo "$(bc <<< $(wc -m<<<$a)-1) $a";done|sort -n
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the
find -printf "%f\n" prints just the file name from the given path. This means directory paths which contain extensions will not be considered.Show Sample Output0find /some/path -type f -and -printf "%f\n" | egrep -io '\.[^.]*$' | sort | uniq -c | sort -rn -
0history | awk '{print $2}' | awk 'BEGIN {FS="|"}{print $1}' | sort | uniq -c | sort -nr | head
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0find . -type f -print0 | xargs -0 -n1 md5sum | sort -k 1,32 | uniq -w 32 -d --all-repeated=separate | sed -e 's/^[0-9a-f]*\ *//;'
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Simpler and without all of the coloring gimmicks. This just returns a list of branches with the most recent first. This should be useful for cleaning your remotes. Show Sample Output
0for k in $(git branch | sed /\*/d); do echo "$(git log -1 --pretty=format:"%ct" $k) $k"; done | sort -r | awk '{print $2}' -
The listing will be nice separated with dashes in chunks of identical files. Output format: Size Inode Mode Count_of_identical_files UID GID Date Time Path/Filename Show Sample Output
0for a in $(find . -xdev -type f -printf '%i\n'|sort|uniq -d);do find . -xdev -inum $a -printf '%s %i %m %n %U %G %AD %Ar %p\n';done|sort -n|awk '{if(x!=$2){print "---"};x=$2;print $0}' -
0ls -l | sort +4n for ascending order or ls -l | sort +4nr for descending order
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couldn't stand previous unsortability of at jobs list Show Sample Output
0atq |sort -k 6n -k 3M -k 4n -k 5 -k 7 -k 1 -
for those without the tree command. Show Sample Output
0find . -ls | sort -k 7 -n - ‹ First < 18 19 20 21 22 > Last ›
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